Monday, February 18, 2013

Continuous Probability Learning

Introduction to continuous probability learning :

Definition: Learning to define continuous probability of an event occurs when the one or more events occurred. Consider any two probabilities A and B. when the event A occur and it depends on the other event which is already occurred then we can say the conditional probability of above two events are P(A | B). Learning  conditional probability of events using the following formula :

`P((A)/(B))=(P(A U B))/(P(A))`

Please express your views of this topic Find the Probability by commenting on blog.

Learning to solve conditional probability problems 1:


Learning some problems to find the conditional probability.

Pro 1:Consider a population, the probability a men life at least 70 years is 0.70 and is 0.65.if he won’t live more than 80 years. If a man is 70 years old, find the conditional probability that he will survive on 80 years. If A subset of B then P (A U B) = P (A)

Solution:Let us take A is the event that he lives to 70 years and B is the event that he will live at least 80 years.

So given that P (B) = 0.55 and P (A) = 0.70

So Conditional probability P (`(B)/(A)) = ( P (A U B)) / ( P (A))`

The given condition is P (A and B) = P (B) = 0.65

Conditional probability P (`(A)/(B)` ) = `(0.65)/(0.70)`

P (`(A)/(B)` ) = 0.9286

Is this topic Introduction to Probability hard for you? Watch out for my coming posts.

Learning to solve conditional probability problems 2:

A box contains red and blue marbles. We are choosing two marbles without replacement. Probability of choosing red and blue marbles is 0.45 and choosing the red marbles on the first draw is 0.57. Find the probability if the second marble is blue if the first one is red?

Solution:Probability of choosing red and blue marbles is 0.45

Probability of choosing red in the first draw is 0.57

So probability of choosing second marble ids blue then the probability is

P (`(Blue)/(Red) = ( P ( Red and Blue))/ (P(Red))`

P (`(B)/(R)` ) = `(0.45)/(0.57)`

P (`(B)/(R)` ) = 0.79 = 79 %

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