Friday, April 12, 2013

Learning Support Math

Introduction for math learning support:

Math support learning  is a most interesting subject comparing to other subjects.It is the lesson for learning support math patterns, numbers, and shapes. Basic concepts of math are  Addition (a + b), subtraction (a-b), multiplication (a*b) and division (a/b) a and b are the numbers or integers. In this article, we are going to see some solved math support learning. I like to share this list of the prime numbers with you all through my article.


Example Problems for math problems:


Learning for support math problem 1:

Perform the Plus operation for 300 and 584

Solution:

Given we need to find the sum of 300 and 584

300

584  (+)

----------------

884

--------------

So the answer for 300 and 584 is 884

Learning for support math problem 2:

Multiplying two numbers 168 and 43

Solution:

The given two numbers 168 and 43

We need to find the product of two numbers

By Multiplying  168 and 43

168 × 43

--------------------

5    0  4

6  7   2

--------------

7  2   2  4

--------------

We get  7  2   2  4

Learning for support math problem 3:

Find equivalent fraction `166/65`

Solution:

Equivalent fraction has to multiply numerator and denominator by same number

Denominator is 65 and the numerator is 166

Multiply the denominator and numerator by 24

= ` (166xx24)/(65xx24)`

=`3984/1560`

So the equivalent fraction is `166/65` is  `3984/1560`

Learning for support math problem 4.

Subtract the two fractions `174/112` and `224/112`

Solution:

The two given fractions are `174/112` and `224/112`

Step1: The given two fractions

`174/112` - `224/112`

Step2: Now we need to find the differences of   `174/112` and `224/112`

`(174-224)/112`

Step3: The difference of 174 and 224 is 50

= - `50/112`

Understanding formula to find percentage is always challenging for me but thanks to all math help websites to help me out.

Few More Example Problems for math problems


Learning for support math problem 5:

Round the number 136 to the nearest 10

Solution:

The given number is 136

The number in 10 places is 3 and the number 1s places is 6

Since the number ten places is 6 so we make the number 6 as zero and we add 1 to 3

So the number 136 grounded to nearest 10 becomes  140

Learning for support math problem 6:

Identify 135 is a prime number or not

Solution:

The given number is 135

We need to identify prime number or not

To identify 135  is a prime number we need to determine in factors

Factors of 135  are 1  3  5  9  15  27  45  135

The number to be a prime number it must have only two factors 1 and itself

So here 135  has eight factors so it is not a prime number

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