Hardest Math Problem to Solve

Introduction to hardest math problem to solve:

Learn and to solve the  hardest math problems involves the operations like addition, subtraction, multiplication and division and it be viewed as ( +,-,`xx` ,÷ ) .By solving the hardest math problems means  it helps in our daily life also without math there is no calculation involved and so every one is learning the math problems.The math problems helps  to increase our mental ability and to think and execute in some pressure situations with out any mistake. Here we are going to see about the article called hardest math problem to solve .


Solved hardest math problem


Math problem 1:

A ice cream manufacturing organization  produces an amount of 4357 ice cream product flavor  in a year. And that company produces three types of ice cream flavors of products like strawberry, Butterscotch, and chocolates. The amount of chocolates was 199 more than the flavors of Butterscotch. Then the strawberries flavor were made four times of the number of chocolates made in this year. Find the number of strawberry was produced by the company in this year?
Solution:

Let we denote as,

A = strawberry, B = Butterscotch, and C = chocolates.

Step 1:

From the given problem we can write as,

A + B+ C = 4357 (1) 

C = A + 199         (2)

B = 4A                   (3).

Step 2:

In step 2 denote the equations 2nd and 3rd in equation 1,

A+ 4A + A +199  = 4357

6A = 4158.

A = 693

So we get there are  693 strawberry  flavor were produced by the ice cream  company in this year.

Step 3:

Apply the value of A in equation 3 we get,

B = 4(693)

B =2772

So we get there are 2772 Butterscotch flavor were produced by the ice cream company in this year.

Step 4:

Apply the value of A and B equation 1 we get,

A + B + C = 4357

693+ 2772 + C =4357

3465+ C= 4357.

C = 892

So we get there are 892 chocolates flavor were produced by the ice cream company in this year.


One more solved hardest math problem


Math problem 1:

Solve the given problem 20(s – 99) – 87s - 18 = 191(s + 15)

The Solutions follows below:

Given expression is,

20(s – 99) – 87s `-` 18 = 191(s + 15)

Multiplying the integer terms

20s – 1980 – 87s – 18 = 191s + 2865.

Grouping the above terms

–67s –-1998= 191s + 2865

Add 1998 on both sides

–67s –1998+ 1998 = 191s + 2865  + 1998

Grouping the above terms

–67s = 191s +4863

Subtract 191s by on both sides

–67s – 191s = 191s – 191s + 4863

Grouping the above terms

–258s = 4863

S = `- 4863/258`

The required answers is 

S = `- 4863/258`