Introduction:
In algebra, the sum of a countable number of monomials is referred as a polynomial. The way of writing a polynomial as a product of two or more simpler polynomials is referred as factorization.
The process of factorization is also known as the resolution of factors. Factoring quadratic polynomials is one of the basic operations of polynomials. The process of factoring the quadratic expression ax^2 + bx +c is explained below: Looking out for more help on Factor a Polynomial in algebra by visiting listed websites.
Method of factoring quadratic polynomials:
Let us consider the coefficients a, b and c as integers and a is not equal to 0. When the coefficients a, b and c satisfy certain conditions, the quadratic expression ax^2 + bx +c can be factorized.
First, we consider a simpler case with a = 1 and b and c as integers.Now, we have to factorize x^2 + bx + c. We try to write the integer constant term c as a product of two integers p and q such that p + q = b. If we find solution in our attempt, then
x^2 + bx + c = x^2 + (p + q)x + pq
= (x^2 + px) + (qx + pq)
= x(x + p) + q(x + p)
= (x + p) (x + q)
General Rule for factoring quadratic polynomials : If the constant term c of quadratic expression x^2 + bx + c can be expressed as a product of two integers p and q such that the sum p + q is the coefficient b of x, then x^2 + bx + c = (x + p)(x + q).
I have recently faced lot of problem while learning free online tutors for algebra, But thank to online resources of math which helped me to learn myself easily on net.
Example for factoring quadratic polynomials
An example for factoring quadratic polynomials is given below:
1) Factorize x^2 + 5x + 6.
Step 1 : Possible factorization of 6 is 6 = 1 x 6
6 = 2 x 3
Step 2 : Sum of factors are 1 + 6 = 7
2 + 3 = 5
Step 3 : Factorization:
Now we need to compare the coefficient of x and the sum of the factors. We find that the sum of the factors 2 and 3 is the coefficient of x. The factorization of quadratic expression is explained below:
x^2 + 5x + 6 = x^2 + (2 + 3)x + 6
= (x^2 + 2x) + (3x + 6)
= x(x + 2) + 3(x + 2)
x^2 + 5x + 6 = (x + 2) (x + 3)
In algebra, the sum of a countable number of monomials is referred as a polynomial. The way of writing a polynomial as a product of two or more simpler polynomials is referred as factorization.
The process of factorization is also known as the resolution of factors. Factoring quadratic polynomials is one of the basic operations of polynomials. The process of factoring the quadratic expression ax^2 + bx +c is explained below: Looking out for more help on Factor a Polynomial in algebra by visiting listed websites.
Method of factoring quadratic polynomials:
Let us consider the coefficients a, b and c as integers and a is not equal to 0. When the coefficients a, b and c satisfy certain conditions, the quadratic expression ax^2 + bx +c can be factorized.
First, we consider a simpler case with a = 1 and b and c as integers.Now, we have to factorize x^2 + bx + c. We try to write the integer constant term c as a product of two integers p and q such that p + q = b. If we find solution in our attempt, then
x^2 + bx + c = x^2 + (p + q)x + pq
= (x^2 + px) + (qx + pq)
= x(x + p) + q(x + p)
= (x + p) (x + q)
General Rule for factoring quadratic polynomials : If the constant term c of quadratic expression x^2 + bx + c can be expressed as a product of two integers p and q such that the sum p + q is the coefficient b of x, then x^2 + bx + c = (x + p)(x + q).
I have recently faced lot of problem while learning free online tutors for algebra, But thank to online resources of math which helped me to learn myself easily on net.
Example for factoring quadratic polynomials
An example for factoring quadratic polynomials is given below:
1) Factorize x^2 + 5x + 6.
Step 1 : Possible factorization of 6 is 6 = 1 x 6
6 = 2 x 3
Step 2 : Sum of factors are 1 + 6 = 7
2 + 3 = 5
Step 3 : Factorization:
Now we need to compare the coefficient of x and the sum of the factors. We find that the sum of the factors 2 and 3 is the coefficient of x. The factorization of quadratic expression is explained below:
x^2 + 5x + 6 = x^2 + (2 + 3)x + 6
= (x^2 + 2x) + (3x + 6)
= x(x + 2) + 3(x + 2)
x^2 + 5x + 6 = (x + 2) (x + 3)