Learning Support Math

Introduction for math learning support:

Math support learning  is a most interesting subject comparing to other subjects.It is the lesson for learning support math patterns, numbers, and shapes. Basic concepts of math are  Addition (a + b), subtraction (a-b), multiplication (a*b) and division (a/b) a and b are the numbers or integers. In this article, we are going to see some solved math support learning. I like to share this list of the prime numbers with you all through my article.


Example Problems for math problems:


Learning for support math problem 1:

Perform the Plus operation for 300 and 584

Solution:

Given we need to find the sum of 300 and 584

300

584  (+)

----------------

884

--------------

So the answer for 300 and 584 is 884

Learning for support math problem 2:

Multiplying two numbers 168 and 43

Solution:

The given two numbers 168 and 43

We need to find the product of two numbers

By Multiplying  168 and 43

168 × 43

--------------------

5    0  4

6  7   2

--------------

7  2   2  4

--------------

We get  7  2   2  4

Learning for support math problem 3:

Find equivalent fraction `166/65`

Solution:

Equivalent fraction has to multiply numerator and denominator by same number

Denominator is 65 and the numerator is 166

Multiply the denominator and numerator by 24

= ` (166xx24)/(65xx24)`

=`3984/1560`

So the equivalent fraction is `166/65` is  `3984/1560`

Learning for support math problem 4.

Subtract the two fractions `174/112` and `224/112`

Solution:

The two given fractions are `174/112` and `224/112`

Step1: The given two fractions

`174/112` - `224/112`

Step2: Now we need to find the differences of   `174/112` and `224/112`

`(174-224)/112`

Step3: The difference of 174 and 224 is 50

= - `50/112`

Understanding formula to find percentage is always challenging for me but thanks to all math help websites to help me out.

Few More Example Problems for math problems


Learning for support math problem 5:

Round the number 136 to the nearest 10

Solution:

The given number is 136

The number in 10 places is 3 and the number 1s places is 6

Since the number ten places is 6 so we make the number 6 as zero and we add 1 to 3

So the number 136 grounded to nearest 10 becomes  140

Learning for support math problem 6:

Identify 135 is a prime number or not

Solution:

The given number is 135

We need to identify prime number or not

To identify 135  is a prime number we need to determine in factors

Factors of 135  are 1  3  5  9  15  27  45  135

The number to be a prime number it must have only two factors 1 and itself

So here 135  has eight factors so it is not a prime number

Math 1010 Answers

Introduction to Math 1010 Answers:

In mathematics, numeration is one of the main sources describing about numerals such as number system. The number is also used for abstract object and symbolic representations of numbers. There is addition, multiplication, division, subtraction operation in math. The common usage of math is to solve the problem and finding the solution. The given problem can be performed by any one of the above operation. Let us see about math 1010 answers in this article.

Please express your views of this topic Row Operations by commenting on blog.

Example Problems for Math 1010 Answers


Using Addition Operation in Math

Example 1:

Add 1000 and 10?

Solution:

Let us add the given problem.

Write the given whole number 1000 first and then write the given whole number 10 second one by one.

1000 (addend)

(+)   10 (addend)

--------------

1010

--------------

The sum for adding 1000 and 10 is 1010.

Using Subtraction Operation in Math

Example 2:

Subtract 2220 and 1210?

Solution:

Let us subtract the given problem.

Write the given whole number 2220 first and then write the given whole number 1210 second one by one.

2220 (minuend)

(-) 1210 (subtrahend)

--------------

1010 (difference)

---------------

The difference for subtracting 2220 and 1210 is 1010.

Using Multiplication Operation in Math

Example 3:

Multiply 101 and 10?

Solution:

Let us write the given problem as in the below form. Here, 101 is multiplicand and 10 is multiplier.

101 ×

10

----------------

1010

----------------

The product for multiplying 101 × 10 is 1010.

Using Division Operation in Math

Example 4:

Divide 9090 by 9?

Solution:

Let us write the given problem is in form of 9090 ÷ 9 and put the divisor on the left side of the division bracket and dividend on the right side of the division bracket.

Check whether the 9 goes into 9. The number 9 should go into 9 for 1 time. Continue with the division method.

9)9090(1010

9

----------------

009

009

----------------

00

-----------------

The quotient for dividing 9090 by 9 is 1010.


Practice Problems for Math 1010 Answers


1. Add 990 and 20.

Answer: 1010

2. Subtract 4880 and 3870.

Answer: 1010

3. Multiply 220 and 5.

Answer: 1010

4. Divide 7070 by 7.

Answer: 1010

How to do Sets in Math

Introduction to do sets in math:

A set is a collection of distinct objects, considered as an object in its own right. Sets are one of the most fundamental concepts in mathematics. Set theory is now a ubiquitous part of mathematics, and can be used as a foundation from which nearly all of mathematics can be derived. Let us see about the concept of how to do sets in math. (Source: Wikipedia)

Please express your views of this topic Set Theory Union by commenting on blog.

Sets in math:


By using two methods we can do the sets in math. They are,

Roster or tabular form
Set-builder form
How to do sets in math by using Roster form:

The elements are separated by using the commas, and the elements are placed inside of braces { }. For example, the set of all odd positive integers less than 8 is expressed in roster form as {1, 3, 5, 7}.

How to do sets in math by using Set-builder form:

For example, in the set {1, 3, 5, 7, 11}, all the elements possess a common property, namely, all are prime number, which are not possessed in any other set. Representing this set by P, we write P = {x: x is a prime numbers in real numbers}


Example problem in set:


Problem1: Find the solution set of the following equation by using roster form x 2 + x – 2 = 0.

Solution:

x 2 + x – 2 = 0 can be expressed as (x – 1) (x + 2) = 0, that is x = 1, – 2.

Therefore, the solution is {1, – 2}.

Problem 2: Find the set {x: x is a positive integer and x2 < 30} in the roster form.

Solution:

By the given we need the following numbers to represent the set -1, 2, 3, 4, 5.

So, the given set in the roster form is {1, 2, 3, 4, 5}.

Problem 3: Find the set A = {1, 4, 9, 16, 25 . . .} by using set-builder form.

Solution:

We may write the set A as A = {x: x is the square of a natural number}

Alternatively, we can write A = {x: x = n2, where n ∈ N}

In this section we have seen about the concept of how to do sets in math.

Mixed Numbers in Math

Introduction to mixed numbers in math:

In math, Mixed number is very important study.  We will study mixed numbers under algebra in math. This is very helpful when using fractions in math

Mixed number is a one form of fraction.  Mixed number is also known as mixed fraction. Mixed number will get by converting improper fraction into mixed fraction.

Mixed number includes an integer then a proper fraction.  The example of mixed numbers are 1 `2/3` , 5 `7/8` , - 1 `6/5` .

For example, convert an improper fraction into mixed number.

`4/3` = 1 `1/3` .

Let us see sample problems involving mixed numbers in math.

Having problem with Find Inverse Function keep reading my upcoming posts, i will try to help you.

Example Problems on Mixed numbers in Math:


Problem 1:

Subtract  `1/2` from 4 `1/2` .

Solution:

First, we need to convert mixed number into improper fraction.  The steps are following,

4 `1/2`

Multiply the denominator by an integer.

4 x 2 = 8

Add that number with numerator.

8 + 1 = 9

Now write the result in the numerator and keep the denominator same.

4 `1/2`  = `9/2`

Now rewrite the operation.

`9/2` – `1/2`

Here the denominator is same in both fractions. So we just subtract numerators and keep the denominator same.

`(9-1)/2` = `8/2` = 4 .

The answer is 4.

Problem 2:

Subtract  - 2 `3/5` from - 1 `3/5` .

Solution:

First, we need to convert mixed number into improper fraction.  The steps are following,

-2  `3/5`

Multiply the denominator by an integer.

2  x 5 = 10

Add that number with numerator.

10 + 3 = 13

Now write the result in the numerator and keep the denominator same.

-2 ` 3/5`  = - `13/5`

Now we need to do same process for another mixed number.

-1 `3/5`

Multiply the denominator by an integer.

1  x 5 = 5

Add that number with numerator.

5 + 3 = 8

Now write the result in the numerator and keep the denominator same.

-1 ` 3/5`  = - `8/5`

Now rewrite the operation.

-1 `3/5` – (- 2 `3/5` ) = -` 8/5` – (-`13/5` )

= - `8/5` + `13/5`

= `13/5` – `8/5`

Here the denominator is same in both fractions. So we just subtract numerators and keep the denominator same.

`(13-8)/5` = `5/5` = 1 .

The answer is 1.

Problem 3:

Multiply the mixed numbers:  -2 `2/3` and  4 `1/10`

Solution:

First, we need to convert mixed number into improper fraction.  The steps are following,

-2 ` 2/3 `

Multiply the denominator by an integer.

2  x 3 = 6

Add that number with numerator.

6 + 2 = 8

Now write the result in the numerator and keep the denominator same.

-2  `2/3`  = - `8/3`

Now we need to do same process for another mixed number.

4 `1/10`

Multiply the denominator by an integer.

4  x 10 = 40

Add that number with numerator.

40 + 1 = 41

Now write the result in the numerator and keep the denominator same.

4 `1/10`  = `41/10`

Now rewrite the operation.

-2` 2/3` x 4` 1/10` = - `8/3` x `41/10`

= - `328/30`

=` -164/15`

= - 10 `14/15`

Understanding hard math problems with answers is always challenging for me but thanks to all math help websites to help me out.

Practice Problems on Mixed numbers in math:


Problem 1:

Find the solution of  -2 `1/5` and -1 `3/4`

Answer:

3 `17/20`

Problem 2:

Find the solution of – 2 `7/8` + 4 `3/8`

Answer:

1 `1/2` .

Problem 3:

Find the solution of `1/6` – 1 `5/6`

Answer:

-1 `2/3`

Learn Online Perpendicular

Introduction to learn online perpendicular lines:

Perpendicular means nothing but when two lines are cross in either direction and form right or 90 degree angles, so a horizontal line  and a vertical line  that cross are perpendicular because they form right angles.
Perpendicular lines are two lines which meet at a right angle. Right angle is 90degrees. Please express your views of this topic Slope of a Perpendicular Line by commenting on blog.


Learn perpendicular lines online through examples


1)Find the equation of the perpendicular line  to y = `(1)/(2)` x-5, passing through the point (4, 10).

Learn perpendicular lines online by using slope-intercept form:

Since the original line has a slope of `(1)/(2)`  , a perpendicular line must have a slope of -2.

Therefore, the equation must look like y = -2x + b.

Substituting the given point in place of x and y we have: 10 = -2(4) + b. Solving, we find that b = 18.

The equation is y = -2x + 18.

Learn perpendicualr lines online by using point-slope form:

Again, the perpendicular slope is m = -2. The equation must look like y - y1= -2(x - x1).

Substituting the given point in place of x1 and y1 we have y - 10 = -2(x - 4).

Rearranging yields y - 10 = -2x + 8 or y = -2x + 18.

2) Show that the lines 6x +3y +9 = 0 and 3x-5y+7 = 0 are perpendicular.

Solution: Given equation of lines as 6x + 3y + 9 = 0 and 3x + 5y+7 = 0

First line:   6x + 3y + 9 = 0                                                Second line:  3x - 5y + 7 = 0

6x + 3y + 9 - 9 = 0 -9                                                              3x - 5y + 7 -7 = 0 -7

6x + 3y = -9                                                                              3x - 5y = -7

6x -6x + 3y = -9 - 5x                                                                3x - 3x - 5y = -7 -3x

3y = -6x - 9                                                                               -5y = -3x-7

3y/3 =  (-6x-9)/3                                                                       5y/5 = (3x+7)/5

y = -5/3x -3                                                                              y =  3/5x +7/5

compare with y = mx + b                                                     compare with y = mx +b

m =`(-5)/(3)` and b = -3                                                              m = `(3)/(5)`  and b = `(7)/(5)`

Condition for lines to be perpendicular is m 1 * m2 = -1

Here, m 1 = `(-5)/(3)`  and  m 2 = `(3)/(5)` ,

m1 * m 2 = `(-5)/(3)` *`(3)/(5)`  =  -1

Therefore the  5x +3y +9 = 0 and 3x-5y+7 = 0 are perpendicular lines.

I have recently faced lot of problem while learning need help with math problems for free, But thank to online resources of math which helped me to learn myself easily on net.

learn perpendicular online -formula


Two lines are perpendicular to each other when the product of their slopes is -1

Let slope of first line is m1

Slope of second line is m2

m1 * m2 = -1

Slope of a line between points (x1,y1) and (x2,y2) is     m =`(y_(2)- y_(1))/(x_(2)- x_(1))`

Equation of line in slope intercept form is y = mx +b , where m is the slope of line and b is the y intercept of line

The equation of all lines perpendicular to the line ax +by +c = 0 can be written as bx –ay +k = 0 for different values of k

Learn Online Slope Intercept

Introduction to learn slope intercept:

Slope:

The Slope can be defined as the ratio of the

rising value to the run value between two points on a line.
change in altitude to the horizontal distance between any two points on the line.
Slope of a line is explained with examples in online.

Intercept:

Intercept of a line is a  point at which a line, curve, or surface intersects an axis.
Intercept is an intercepted segment of a line.
Intercept of a line can be learning easily through online.

I like to share this Slope Intercept Form Equation with you all through my article.

Learn online slope:


In the given two points (x1,y1) and (x2,y2) on a line, the slope m of the line is given by

m = (y2 - y1) / ( x2 - x1 )

Example 1: Find the slope of the line segment joining the points (1, 2) and (13, 8).

Solution:

Let  (x1,y1) = (1, 2)

(x2,y2) =(13,8)

m = ( 8 - 2 ) / ( 13 - 1 )

m = 6 / 12

m = 1 / 2

m = 0.5

Therefore, the slope of a line is 0.5

Example 2: Find the slope of the line segment joining the points (6, 10) and (4, 20).

Solution:

Let (x1,y1) = (6,10)

(x2,y2) = (4,20)

m = ( 20 - 10 ) / ( 4 - 6 )

m = 10 / (-2)

m = -5

Therefore, the slope of a line is  -5

This is how we can learn slope of a line through online.


Learn online intercept:


X - intercept

The x-intercept of a line is defined as the point at which the line cuts the X-axis.

Y - intercept

The y-intercept of a line is defined as the point at which the line cuts the Y-axis.

The following example problem helps you to learn intercept through online.

Example: Find X and Y intercept of the equation 6x + 8y =24

To find X intercept, plug y =0

6x + 8(0) =24

6x =24

x = 24 / 6

x = 4

Therefore, X-intercept is ( 4,0 ).

To find y intercept , plug X=0

6x + 8y =24

6(0) + 8y =24

8y =24

y = 24 /8

y =3

Therefore, Y-intercept is ( 0,3 ).

Learn Numeric System

A Numeric system contains real numeric/numbers. In this document we will say numeric s system as numbers.

The real numeric/numbers is further divided into two parts:

• Rational Numeric system
• Irrational Numeric system

I like to share this Lowest Common Multiple with you all through my article.

The rational numeric system is sub divided into further 4 parts namely:

• Natural numeric system
• Whole numeric system
• Integer’s numeric system

Irrational Numeric system:

Irrational Numeric system is not in the form of a/b i.e., if a number is there say 2.5 it can be written in fraction as 5/2 so it is not a irrational number as it is in the form of a/b. And with this we can say that this type of numeric system is not a perfect square, for e.g. `sqrt(15)` or `sqrt(17)` or any number which is not a perfect square comes in irrational numeric system.

Rational Numeric System:

Natural Numeric System: In natural numeric system we have all the natural numbers say 1,2,3....`oo` , these numbers are say increased by 1 and these does not include 0. These numbers are generally represented by 'N'.
Whole Numeric System:  In these type of numeric system we have numbers from 0,1,2,3....`oo`
Integer Numeric System: In these type of Numeric system we have numbers from -`oo`  to +`oo` , say ....-2,-1,0,1,2,... . These numbers inclue both positive and negative numbers. These are generally represented by 'Z'.
Fration Numeric System: In these type of numeric system we have a number in form of a/b, where a and b represents numerator and denominator resp. , e.g., 2/3 is fraction. These are generally represented by  'F'.